Диссертация (1150357), страница 2

Просмтор этого файла доступен только зарегистрированным пользователям. Но у нас супер быстрая регистрация: достаточно только электронной почты!

Текст из файла (страница 2)

..,. ...,–,–.. .ДҚ72Ж.V(r). . .,,.,,,μДҚ73].μ.,,. ДҚ74].,52.ДҚ75ЖҚμ.,,,..,,,.I.4.-,,..,ДҚ76],,( = 24.3),( = Қ.0λқ· ),(-= 7κ.3қ° ).,,,,.,қη %.,..ζ0 - η0%қ-3,.53.70 - κ0 %,.-.ДҚ77Ж,,,.,μ32 5·12 H2 ;2 5κκ.η2;Қ7.η; ζθ.0;·H2 ,2 5·3. %.,-,.,,,.,,.,...қη%.,,.,-,54.ДҚ78],,.,-,,,,.,,,,.,,,,,,.ДҚ79-181Ж,.,.55II.II.1..,( = 0.қ3.,,= 0.55= Қ.0қ№Қ-3),.№ ζ, 5 ( = 0.Қλ,,=0.ζқ),,.№θ,№7 –№θ().№η.(),ζ00(/),,..()(Қ00),,(()).θ0-65θ.,.–56( .

.)(Қ).вHCХ3ζ0 - 45° .μCH2HCH3O+nCH2-HCOOHHNHCnNH3OC(I)HμHNH2CCH3CHH2CNHH2CHCɇ Ɉ2CH3OCnH2CnHOCH3HCCH3(II).,№θ.№7,3.қ,-(. .)...μқμ357HOOOHn**NHSCOOH*nCNH*NH2COOHNCSOHO(III)HO,,μεКХЯОЫЧГОЭКЬТгОЫσКЧШ-ГS ()( .. қ.Қ).. қ.Қ.= 0.қ3( ),= 0.ηη, = 0.Қλ( ), = 0.ζқ( )58. қ.Қ.,,−(()..қ.қ)..қ.қ.= 0.қ3= Қ.0қ( ), = 0.ζқ( ),= 0.ηη( ),( ).Қ.ηλ.Қ.0λ /3.,:596  1012Ss ,S, /; –2(2.1),,3ρs -Қ.қ.Қ..,№,,210.2320.5531.024,,//2% ( .

.)23.91.1812.5210.01.0010.005.42.6810.800.1929.00.858.2650.4213.10.7810.6060.4512.20.346.070.5011.0-0.05-COOH--NH2(NaCl5.5 – 6.5)..SОЯОЧεЮХЭТεОЭХОЫTШХОНШ ().((,,)-),σКτH.[182Ж..қ.3608001/R,S/c1/R,S/c2001506004002 VNaOH,02002446VNaOH,. қ.3.( = Қ.0қ) ( )( = 0.Қλ) ( )..[183]:6 1012N  s  3 ,Қ .N,(2.2), ρs -, /3;–.0.00қ%, зҚ∙1012/–/3–зҚ∙107.3.3.0 – λ.0.61..,(«-NaCl»),0.0Қ0.00Қ ;,«».II.2II.2.1(,)-0.3– Қ0.0..,.,.,.-,(Uef).μ().(.қ.ζ),,62,., . ..( = 0.қ3= 0.Қλ,= 0.ζη,= 0.η0),0.00Қ - 0.Қη/().NaClMalvernZetasizerNano-ГSқη°U-(DTSҚ0θ0).. қ.ζ.,(қ.η).-II.2.2№ қ,3,η ( = 0.ηηUef,= Қ.0қ,= 0.42)(қ.3).,,63NaCl (0.00ҚpH 3.0 – 9.0 .=,∙ ∙ℎ∙�(2.3)�∙ ∙/( ∙ );-1; h–); t –, ;I––2,t, ; K –∙/ )(қ.3)μUefUef –(/ – 0.15,; l–, .Κ(қ.3)HAσσA HI κ733қ0° ,±Қ%.,-4,ы[77,184-188Ж.яБ5-50М.

Пяыыя.0 – 30030,300.Қ00 ,,0.010 / .. қ.η64.қ.η.(h)(0.λ7-1.04);0.қҚС0.7λС,,,,[58].,[189],,,,.0.қҚ С.,(. қ.θ).,0.6/0.40.2000.20.40.60.8,11.2.қ.θ.= 0.ηηNaCl= 10-3/Қ0-3,,NaClҚ0-2/Қ0-1/.65II.2.3.(қ.3)Uef..κ=√–С� 0,(1.6×10-19,0(-r,), r –-�,(2.4)/ , z–, e–ε–),–(κ.κη·Қ0-12 / ),(Қ.3κ×Қ0-23),–k–(қλκ ).r >>Қ--(қ.ζ) ДҚλ0-193]:Sm–(U ef (2.5) 0( ),–· ).,,ДθθЖ.E,E = 0.8387×Uefμ=�+ , �− -= ,q0(қ0°�+ +�−�−=E(q0)):,(2.6)(2.7).NaClr:y0 ,(W):NaCl �+ = �− = ,=.-66W Wy0 kTe(2.8)3.3-3.ζ.II.3II.3.1ДҚλ4-198Ж..-4,. қ.λ.қ.λ.(,),(nt),.,θқ0η3қ..қ.Қ067( = 0.ηη).,,η,(қ0%).,,.731/n*10 ,134213(1) (2) (3) -2050l =620l =532100150200250 t,300.қ.10)(a = 0.551-( ann twtқ)(.(2.9)3),,(қ.λ).nantwt(2.9)a’ –, nt –t, w –,,,3/,t–.,,.,68μ(n ≤1010),1....2..–,,.3.,Д195].,-,0.қ..қ.Қ1(a = 0.ζқ(1/n)ηNaCl.(n0)),,.қ0% (қ),n0 = (2.90.6)×106/3–.30.,,.69,,,.8731/n*10 ,765241322050100150250t,200300.қ.11( = 0.ζқ)(Қ).қ-.( = 0.23«)»-7623 [199].VҚҚ3-..71/n*10 ,(1)(2)(3)143123102813642050100150200250 t,300.қ.Ққ(a = 0.қ3)(Қ)(қ)..3 -70,,(.2.12).Д200Ж,(,.

қ.Қ3).,0.қ().,..қ.Қ3μ(a=/ζ),––ё(a= /Қ0),–(К> ) [201] (a –),-,, a-b—.II.3.2,.,,,71,,.3Қη--қ7η0.± Қ%.,,0,3%.±ққққ0қ00,33η°қ0Қ0°.0,3-.θ,3-Қη-Қ0.0.03қ-3Қ.00,Қ.30 Дқ02].( ),(n),(n’),( ),( ).()((қ.Қ0),(n’ )қ.ҚҚ)μ2  r n 'n'n'n'(2.10);(2.11),=қ.3 Dn'—(2.12)(Қ.ηλ), n '–72, й,  –; —,,D(2.12).1) K  , n'  —(2) n* —,);. .(қ.Қ3)μ ~(2.13) n*D( )-қ3Қη-750,.(қ.Қζ)clg D  B  n * lg  ,B —(2.14)..K  , n'(қ.10),,,(n,./)-3(қ.Қη)1,26 1017 n 2  K  , n '   2 ,  -(2.15)(2.16)n'(2.16).73.қ.Қζ.– D( )(5.5 – θ.η).,.қ.Қζ..,D( )..қ.Қζ.lgD(lg ).,,,,№Қ n’=қ.θ73,= 0.ққ,,( =0.Қλ).,,Қζ%,(20%).,( .

.).0DlgD 2.450.52.552.652.752.85-0.20.4lgλ-0.40.3-0.60.2-0.80.1-10.0300400500600700λ,y = -2,673x + 6,122-1.2800-1.4.қ.Қζ( = 0.Қλ)( )(= 315 – 7κ0) ( )274II.3.3..,ViμVm=-�+(2.17)( )H. Oshima, T. Healy,L. White [203Ж,�∗�=++r–(2.18):�−�ℎch+h��ℎ{−−�ℎ−�ℎ++chh, h-�ℎ�ℎ+ −−ℎ}[ − thℎ]+−++ −ℎ[cthℎ− ]−(2.18),(қ.Қλ)μVi*∗�=���(� +� )+(қ.қҚ)� �{�[+�+exp⁡ − ℎ−exp⁡ − ℎ]+(қ.Қκ)[ + exp⁡ −(қ.Қλ)ℎ ]}(2.19)(қ.қ0):�∗�=∗�=�+�� +� {{− ℎ [ − th[+exp⁡ − ℎ−exp⁡ − ℎ]+ℎ]−�ℎ−ch1  2 -�ℎ�ℎ[ + exp⁡ −zeze, kTkTh−}(2.20)ℎ ]}(2.21)(2.22).-.-,,[204]:75 1 AaV m1211,77hpp< 0,5(2.23)Aa2,452,170,59V  2 3m601020hp8p4p0,η <p < ∞,(2.24)p = 2h/, А –(),[205], –5.9·10-21710-8,Д206].(қ.қ3)(қ.қζ).,«»,.(W1)«»(қ.қη)μ= [∫V(u) –∞+exp⁡�] × [∫�-∞+exp⁡Vi(u)��,�−] ,;VА(u)u = h/r –(2.25).(қ.қθ):=«+++(2.26)»(W2)(қ.қ7)[207]:=(+ℎ���{}��� ) ∞∫ℎ+�� �−exp{}��,(2.27)76W2 –,hmin –.,,,(2.28)d [134],μ⁡N2 –Қ/,3.≅ 6�, n0 –�, N2≈Қ0,⁡��A�⁡⁡(2.28)⁡⁡,(қ.қλ)μ(қ.қκ)≅ 6����A(2.29)⁡⁡⁡II.3.4..

.[171]μа=+ 6�s,Дқ0κЖ,V–Г(2.30),Γ = ∫�< exp⁡ −�,�, u–,((2.32)«») V(u) = 0(2.31)h/r.V(u) = -0.1 kT.(2.33):�а⁡�а==�� ⁡Г(2.32),(2.33)77–(2.34):⁡ =–��(2.34),,· ,R–,D–μ=���.(2.35)78III.III.1.NaCl.NaCl(),,( = 0.55= 1.02).= 0.42(2.5).( = 0.23)= 0.19εКХЯОЫЧГОЭКЬТгОЫσКЧШ-ZS.III.1.1.()= 1.02= 0.55(,),= 0.42,.3.Қ–3.ζ.(2.3).,–,.Uef,3.қ)–.Қ.қ(3.Қ-79Uef*108,42(1) а = 0.55(2) а = 1.02(3) а = 0.42/( *c)23034567Н 89-221-4.3.Қ.( = 0.55) (Қ); ( = 1.02) (3)( = 0.420.00Қ/) (қ)NaCl.8Uef*10 , 4(1) а = 0.55(2) а = 1.02(3) а = 0.42/( *c)223034567Н89-221-4.3.қ.( = 0.55( = 0.42) (3)) (Қ); ( = 1.020.0Қ/ σКCХ.) (қ)80,–.- NH2.

3.ζUef.8Uef*10 , 4(1) а = 0.55(2) а = 1.02(3) а = 0.42/( *c)220334567Н89-221-4.3.3.( = 0.55) (Қ); ( = 1.02σКCХ( = 0.42().) (3)) (қ)0.Қ0.Қη(.3.ζ,Қ - 3),..//σКCХ818Uef*10 ,24(1) a = 0.55(2) a = 1.02(3) a = 0.42/( *c)230123-lgCNaCl-22-41.3.ζ.( = 0.55) (Қ); ( = 1.02) (қ)) (3)( = 0.42NaCl,III.1.2.,,Uef.-., Uef0.қ0.εКХЯОЫЧГОЭКЬТгОЫσКЧШ-ГS,(),.,,.( = 0.55Uef).(2.5) (.3.η82қ);,,.3.η (1).801706025040(1)(2)30201034.3.η567pH89( = 0.55-),εКХЯОЫЧГОЭКЬТгОЫσКЧШ-ГS (Қ)(қ),NaCl= 0.0Қ/ ..3.η,,-.λ.0,(7%).-.III.1.3.,.,.83,Д23Ж.,,.– 4-4'---4-Д31,208].«)( = 0.55»..-.,.3.θ,,,,,..(1) СNaCl = 0.00170- ,/(2) СNaCl =0.0160/НН 4.02504030201100010.3.θ( = 0.55NaCl= 0.0Қ20304050,ы)NaCl/ζ.0 (қ).= 0.00Қ/(Қ)84,,(η).-III.1.4.-(2.5).,,.,..,,,.,,.,,,,.ё,Д66-68].қη – Қη00.Қ< r<η0, .r,–,-1,r–853.Қ,№Қ-r= 0.қ3,Sm.№қ-W,,Sm-rNaCl= 0.ηη= 0.00Қ№3-W,r-= Қ.0қ,Sm-W,/3.016.085.3*5.385.5417.9*17.9158.6311.4*11.44.012.4721.7*21.766.3438.141.2123.0434.235.45.8-6.212.0050.454.063.8856.661.8118.4741.844.49.012.0058.267.763.8659.164.0118.4351.954.9= 0.0Қ/NaCl3.039.433.1*3.194.2912.5*12.5174.869.3*9.34.038.0822.0*22.091.0725.226.0168.8924.124.15.8-6.237.9535.641.190.7556.960.7168.3049.842.79.037.9555.462.390.7556.960.7168.3054.056.2NaCl= 0.Қ/3.0120.482.7*2.7641.1014.4*14.41188.9511.0*11.04.0120.0515.2*15.2638.7924.624.61184.5219.2*19.25.8-6.2120.0116.1*16.1638.5754.355.01184.2639.740.99.0120.0116.5*16.5638.5754.355.01184.2549.350.1*,.,қη3.Қ.( = 1.02),,,,r,7%.= 0.55= 1.02,= 0.23ққ%,...8670 ,16025040/(1) CNaCl = 0.001/(2) CNaCl = 0.0130/(3) CNaCl = 0.1203100345.3.767)CNaCl = 0.00ҚCNaCl = 0.Қ9pH-( = 0.238/(Қ), CNaCl = 0.0Қ// (3)..

3.7 - 3.λ(,)μ.-3.0 – λ.0.,,(3.0),,,( = 0.қ3=1.0қ),( = 0.ηη).,σКCХ,,((қ),-,– 7% .)8770 ,60504032130/(1) CNaCl=0.001/(2) CNaCl=0.0120/(3) CNaCl=0.110345.3.κ.( = 0.5567pH89)CNaCl = 0.00Қ/ (Қ), CNaCl = 0.0Қ/ (қ), CNaCl = 0.1/ (3).ζ.0λ.0,3.0( = 0.қ3( = 0.ηη),,-).-,.,,= 0.қ3(Қ.ҚκҚ.00/ 2).,= 1.02(қ.θκ-/ 2).,.= 0.ηη8870/(1) CNaCl=0.001 ,60/(2) CNaCl=0.01/(3) CNaCl=0.1501402303201034.3.λ.67pH89)( = 1.025CNaCl = 0.00ҚCNaCl = 0.Қ/(Қ), CNaCl = 0.0Қ/ (3)..3.Қ0(CNaCl = 0.0Қ)/ .70 ,26015034030(1) а = 0.23(2) а = 0.55(3) а = 1.0220100345.3.Қ0.( = 0.23CNaCl = 0.0167pH89)(Қ);/( = 0.55)(қ),( = 1.02)(3)/(қ),89-III.1.5.( = 0.ζқ( = 0.Қλ),).,3.қ.3.қ,№ζr,.= 0.Қλ№5,NaCl = 0.00ҚSmW= 0.ζқ,Smr/W,3.013.2849.264.230.9938.945.54.010.345.560.922.9833.840.55.8-6.29.9139.853.321.9220.3*20.39.09.9114.1*14.121.919.7*9.7NaCl= 0.0Қ/3.073.1658.153.1160.230.932.04.069.9341.643.5154.827.828.75.8-6.269.7621.2*28.9154.218.8*18.89.069.7619.8*16.0154.26.5*6.5NaCl= 0.Қη/3.0221.533.033.7489.626.526.74.0220.733.534.2487.817.7*17.75.8-6.2220.624.1*24.1487.611.4*11.49.0220.67.6*7.6487.6-2.9*-2.9*,.,( = 0.19)34%,,( = 0.42NaClθ.θ)(қ0%)..-90()(.3.ҚҚ - 3.Ққ),,., ,,.70(1) CNaCl=0.0016050/(2) CNaCl=0.01/(3) CNaCl=0.15/140302203100.3.ҚҚ.CNaCl = 0.00Қ34-567/ (Қ), CNaCl = 0.0Қ89 pH( = 0.Қλ/ (қ), CNaCl = 0.Қη)/ (3),, ,.70/(1) CNaCl=0.0016050(2) CNaCl=0.01/(3) CNaCl=0.15/403020100.

3.Ққ.3CNaCl = 0.00Қ4-567/ (Қ), CNaCl = 0.0Қ89 pH( = 0.ζқ/ (қ), CNaCl = 0.Қη/ (3))91.3.Қ3= 0.Қλ(Қ)= 0.ζқ(қ)NaCl 0.0Қ,/ .,,(0.κη= 0.ζқ0.7κ/2= 0.19).70,60(1) а=0.19(2) а=0.4250403020110203. 3.Қ3.(Қ)( = 0.ζқ45678pH) (қ)9CNaCl = 0.0Қ( = 0.Қλ)/,.,,,«».,92CNaCl = 0.Қη/ .,μ қζ.Қ( = 0.Қλ)ҚҚ.ζ( = 0.ζқ).III.2.0.00Қ/ – 0.Қη/ .III.2.1.(a = 0.23),,-.m..3.Қ43.0CNaCl = 0.01/(Қ)(қ).(.3.Қ4),(.),,,.,.934m32121(1)(2)050100150200250300 t,.3.14( = 0.23)3.0CNaCl = 0.0Қ(Қ)/ ,/(n0 = 1.1×107(2) (n0 = 3.6×1011/33))III.2.2.(a = 0.23)III.2.2.1 Эяч(a = 0.βγ3.0CNaCl = 0.001, 0.0Қ0.Қη)/.3.Қη..,.CNaCl = 0.00Қ(m = 3.Қ (Қ),CNaCl = 0.0Қ/ηm = 2.5/ – m = қ.7 (қ),CNaCl = 0.Қ/ –3).( = 0.23λ.0NaCl.3.Қθ ()).944m13232/(1) CNaCl=0.001/(2) CNaCl=0.011/(3) CNaCl=0.1050100150200250300 t,.3.Қη( = 0.23()3.0Қ), 0.0Қ (қ), 0.Қ (3)NaCl: 0.001/ ; (n0 = 3.6×1011/3)4m/(1) CNaCl=0.0013/(2) CNaCl=0.01/(3) CNaCl=0.1322110504100150200(3) CNaCl=0.1t,/(2) CNaCl=0.013300/(1) CNaCl=0.001m250/32121050100150200250300 t,.3.Қθ( = 0.23)( )σКCХμ 0.00Қ ((n0 = 1.1×107/3).Қ), 0.0Қ (қ), 0.Қ (λ.0 ( )3)/ ;95η(.3.Қθ.

Характеристики

Список файлов диссертации