Subnetting Assignment ответы (1130582)
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Subnetting Asssingment 1 – SolutionsCIS 81 (100 points)Problem 1Host IP AddressMajor Network Mask172.30.1.33255.255.0.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts172.30.0.0172.30.255.25516 bits65,534 hostsSubnetNumberNumbersubnetNumberNumber255.255.255.08 bits255 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts per SubnetSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for this Subnet8 bits254 hosts per subnet172.30.1.0172.30.1.0172.30.1.254172.30.1.255Major Network Information172.30.1.33255.255.0.0Network Address172.30.0.0101011001111111100011110111111110000000100000000001000010000000010101100000111100000000000000000Network Broadcast Address172.30.255.2551010110000011110111111111111111100011110111111110000000111111111001000010000000000011110000000010000000000011110000000010000000100011110000000011111111000011110000000011111111116 host bits216 – 2 = 65,536 – 2 = 65,534 hostsSubnet Information172.30.1.3310101100255.255.255.011111111Subnet Address172.30.1.010101100First Host of this subnet172.30.1.110101100Last Host of this subnet172.30.1.25410101100Broadcast of this subnet172.30.1.25510101100Subnets: 8 subnet bits, 28 – 1 = 256 – 1 = 255 subnetsHosts: 8 host bits, 28 – 2 = 256 – 2 = 254 hosts per subnet1Subnetting Asssingment 1 – SolutionsCIS 81 (100 points)Problem 2Host IP AddressMajor Network Mask172.30.1.33255.255.255.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts172.30.1.0172.30.1.255254 hostsSubnetNumberNumbersubnetNumberNumberSubnet255.255.255.2526 bits63 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts perSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for thisSubnet2 bits2 hosts per subnet172.30.1.32172.30.1.33172.30.1.34172.30.1.35Major Network Information172.30.1.33255.255.255.0Network Address172.30.1.0101011001111111100011110111111110000000111111111001000010000000010101100000111100000000100000000Network Broadcast Address172.30.1.255101011000001111000000001111111110001111011111111000000011111111100100001111111000001111000000001001000000001111000000001001000010001111000000001001000100001111000000001001000118 host bits28 – 2 = 256 – 2 = 254 hostsSubnet Information172.30.1.3310101100255.255.255.25211111111Subnet Address172.30.1.3210101100First Host of this subnet172.30.1.3310101100Last Host of this subnet172.30.1.3410101100Broadcast of this subnet172.30.1.3510101100Subnets: 6 subnet bits, 26 – 1 = 64 – 1 = 63 subnetsHosts: 2 host bits, 22 – 2 = 4 – 2 = 2 hosts per subnet2Subnetting Asssingment 1 – SolutionsCIS 81 (100 points)Problem 3Host IP AddressMajor Network Mask192.192.10.234255.255.255.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts192.192.10.0192.192.10.2558 bits254 hostsSubnetNumberNumbersubnetNumberNumberSubnet255.255.255.2485 bits31 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts perSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for thisSubnet3 bits6 hosts per subnet192.192.10.232192.192.10.233192.192.10.238192.192.10.239Major Network Information192.192.10.234255.255.255.0Network Address192.192.10.0110000001111111111000000111111110000101011111111111010100000000011000000110000000000101000000000Network Broadcast Address192.192.10.255110000001100000000001010111111111100000011111111000010101111111111101010111110001100000000001010111010001100000000001010111010011100000000001010111011101100000000001010111011118 host bits28 – 2 = 256 – 2 = 254 hostsSubnet Information192.192.10.23411000000255.255.255.24811111111Subnet Address192.192.10.23211000000First Host of this subnet192.192.10.23311000000Last Host of this subnet192.192.10.23811000000Broadcast of this subnet192.192.10.23911000000Subnets: 5 subnet bits, 25 – 1 = 32 – 1 = 31 subnetsHosts: 3 host bits, 23 – 2 = 8 – 2 = 6 hosts per subnet3Subnetting Asssingment 1 – SolutionsCIS 81 (100 points)Problem 4Host IP AddressMajor Network Mask171.68.99.71255.255.0.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts171.68.0.0171.68.255.25516 host bits65,534 hostsSubnetNumberNumbersubnetNumberNumber255.255.240.04 bits15 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts per SubnetSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for this Subnet12 bits4,094 hosts per subnet171.68.96.0171.68.96.1171.68.111.254171.68.111.255Major Network Information171.68.99.71255.255.0.0Network Address171.68.0.0101010111111111101000100111111110110001100000000010001110000000010101011010001000000000000000000Network Broadcast Address171.68.255.2551100000011000000111111111111111101000100111111110110001111110000010001110000000011000000011000000000000011000000011000000000000111000000011011111111111011000000011011111111111116 host bits216 – 2 = 65,536 – 2 = 65,534 hostsSubnet Information171.68.99.7110101011255.255.240.011111111Subnet Address171.68.96.011000000First Host of this subnet171.68.96.111000000Last Host of this subnet171.68.111.25411000000Broadcast of this subnet171.68.111.25511000000Subnets: 4 subnet bits, 24 – 1 = 16 – 1 = 15 subnetsHosts: 12 host bits, 212 – 2 = 4,096 – 2 = 4,094 hosts per subnet4Subnetting Asssingment 1 – SolutionsCIS 81 (100 points)Problem 5Host IP AddressMajor Network Mask217.200.3.219255.255.255.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts217.200.3.0217.200.3.2558 bits254 hostsSubnetNumberNumbersubnetNumberNumberSubnet255.255.255.2243 bits7 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts perSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for thisSubnet5 bits30 hosts per subnet217.200.3.192217.200.3.193217.200.3.222217.200.3.223Major Network Information217.200.3.219255.255.255.0Network Address217.200.3.0110110011111111111001000111111110000001111111111110110110000000011011001110010000000001100000000Network Broadcast Address217.200.3.255110110011100100000000011111111111100100011111111000000111111111111011011111000001100100000000011110000001100100000000011110000011100100000000011110111101100100000000011110111118 host bits28 – 2 = 256 – 2 = 254 hostsSubnet Information217.200.3.21911011001255.255.255.22411111111Subnet Address217.200.3.19211011001First Host of this subnet217.200.3.19311011001Last Host of this subnet217.200.3.22211011001Broadcast of this subnet217.200.3.22311011001Subnets: 3 subnet bits, 23 – 1 = 8 – 1 = 7 subnetsHosts: 5 host bits, 25 – 2 = 32 – 2 = 30 hosts per subnet5Subnetting Asssingment 1 – SolutionsCIS 81 (100 points)Problem 1Host IP AddressMajor Network Mask172.30.1.33255.255.0.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts172.30.0.0172.30.255.25516 bits65,534 hostsSubnetNumberNumbersubnetNumberNumber255.255.255.08 bits255 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts per SubnetSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for this Subnet8 bits254 hosts per subnet172.30.1.0172.30.1.0172.30.1.254172.30.1.255Problem 2Host IP AddressMajor Network Mask172.30.1.33255.255.255.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts172.30.1.0172.30.1.255254 hostsSubnetNumberNumbersubnetNumberNumberSubnet255.255.255.2526 bits63 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts perSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for thisSubnet2 bits2 hosts per subnet172.30.1.32172.30.1.33172.30.1.34172.30.1.356Subnetting Asssingment 1 – SolutionsCIS 81 (100 points)Problem 3Host IP AddressMajor Network Mask192.192.10.234255.255.255.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts192.192.10.0192.192.10.2558 bits254 hostsSubnetNumberNumbersubnetNumberNumberSubnet255.255.255.2485 bits31 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts perSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for thisSubnet3 bits6 hosts per subnet192.192.10.232192.192.10.233192.192.10.238192.192.10.239Problem 4Host IP AddressMajor Network Mask171.68.99.71255.255.0.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts171.68.0.0171.68.255.25516 host bits65,534 hostsSubnetNumberNumbersubnetNumberNumber255.255.240.04 bits15 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts per SubnetSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for this Subnet12 bits4,094 hosts per subnet171.68.96.0171.68.96.1171.68.111.254171.68.111.2557Subnetting Asssingment 1 – SolutionsCIS 81 (100 points)Problem 5Host IP AddressMajor Network Mask217.200.3.219255.255.255.0Major (Base) Network AddressMajor Network Broadcast AddressTotal Number of Host BitsNumber of Hosts217.200.3.0217.200.3.2558 bits254 hostsSubnetNumberNumbersubnetNumberNumberSubnet255.255.255.2243 bits7 subnetsMaskof Subnet Bitsof Usable Subnets (zeroused)of Host Bits per Subnetof Usable Hosts perSubnet Address for this IPAddressIP Address of First Host on thisSubnetIP Address of Last Host on thisSubnetBroadcast Address for thisSubnet5 bits30 hosts per subnet217.200.3.192217.200.3.193217.200.3.222217.200.3.2238.
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