Е. Деза_ М.М. Деза. Энциклопедический словарь расстояний (2008) (1185330), страница 90
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ÉËÔÂÏÂÚ – ˝ÚÓ˜‡ÒÚ¸ ÒÚËı‡, ÒÓ‰Âʇ˘‡fl Î˯ÌËÈ ÒÎÓ„.åÂÚ ‚ ÏÛÁ˚Í (ËÎË ËÚÏ): ‡ÁÏÂÂÌÌÓÒÚ¸ ËÚÏ˘ÂÒÍÓ„Ó ËÒÛÌ͇ ÏÛÁ˚͇θÌÓÈÒÚÓÍË, ‰ÂÎÂÌË ÍÓÏÔÓÁˈËË Ì‡ ‡‚Ì˚ ÔÓ ‚ÂÏÂÌË ˜‡ÒÚË Ë ‰‡Î¸ÌÂȯ Ëı‡Á·ËÂÌËÂ. àÁÓÏÂÚËfl – ËÒÔÓθÁÓ‚‡ÌË ËÏÔÛθÒÓ‚ (ÌÂÔÂ˚‚ÌÓÈ ÔÓÒΉӂ‡ÚÂθÌÓÒÚË ÔÂËӉ˘ÂÒÍËı ͇ÚÍÓ‚ÂÏÂÌÌ˚ı ‚ÓÁ‰ÂÈÒÚ‚ËÈ) ·ÂÁ ͇ÍÓÈ-ÎË·Ó ÛÔÓfl‰Ó˜ÂÌÌÓÒÚË, ‡ ÔÓÎËÏÂÚËfl – ËÒÔÓθÁÓ‚‡ÌË ‰‚Ûı ÏÂÚÓ‚ Ó‰ÌÓ‚ÂÏÂÌÌÓ.åÂÚÓÏÂÚ ‚ ωˈËÌ – ËÌÒÚÛÏÂÌÚ ‰Îfl ËÁÏÂÂÌËfl ‡Áχ χÚÍË.
Ç Ì‡ËÏÂÌÓ‚‡ÌËflı ‡Á΢Ì˚ı ËÁÏÂËÚÂθÌ˚ı ËÌÒÚÛÏÂÌÚÓ‚ ‚ ÍÓ̈ ÒÎÓ‚‡ ÔËÒÛÚÒÚ‚ÛÂÚÚÂÏËÌ ÏÂÚ.åÂÚ˘ÂÒ͇fl ÂÈ͇ – ˝ÏÔˢÂÒÍÓ ԇ‚ËÎÓ ‰Îfl ÔË·ÎËÊÂÌÌ˚ı ÔÓ‰Ò˜ÂÚÓ‚ ̇ÓÒÌÓ‚Â Ôӂ҉̂ÌÓÈ Ô‡ÍÚËÍË, ̇ÔËÏÂ, ÒÚÓÓ̇ ÒÔ˘˜ÌÓ„Ó ÍÓӷ͇ ‡‚̇ 5 ÒÏ,‡ 1 ÍÏ – ÔËÏÂÌÓ 10 ÏËÌÛÚ ıÓ‰¸·˚.éÚÏÂË‚‡ÌË – ÚÂÏËÌ, ˝Í‚Ë‚‡ÎÂÌÚÌ˚È ËÁÏÂÂÌ˲; ÏËÍÓÏÂÚËfl – ËÁÏÂÂÌËÂÔÓ‰ ÏËÍÓÒÍÓÔÓÏ.åÂÚÓÎÓ„Ëfl – ̇ۘ̇fl ‰ËÒˆËÔÎË̇, ËÒÒÎÂ‰Û˛˘‡fl ÔÓÌflÚË ËÁÏÂÂÌËfl.åÂÚÓÌÓÏËfl – ËÌÒÚÛÏÂÌڇθÌÓ ËÁÏÂÂÌË ‚ÂÏÂÌË.åÂÚÓÒÓÙËfl – ÍÓÒÏÓÎÓ„Ëfl, ÓÒÌÓ‚‡Ì̇fl ̇ ÒÚÓ„Ó ˜ËÒÎÓ‚˚ı ÒÓÓÚ‚ÂÚÒÚ‚Ëflı.ÄÎÎÓÏÂÚËfl – ̇Û͇ Ó· ËÁÏÂÌÂÌËË ÔÓÔÓˆËÈ ‡Á΢Ì˚ı ˜‡ÒÚÂÈ Ó„‡ÌËÁχ ‚ÔÓˆÂÒÒ ÓÒÚ‡.ÄıÂÓÏÂÚËfl – ̇Û͇ Ó ÚÓ˜ÌÓÏ ‰‡ÚËÓ‚‡ÌËË ‡ıÂÓÎӄ˘ÂÒÍËı ̇ıÓ‰ÓÍ, ÓÚÌÓÒfl˘ËıÒfl Í ‰‡ÎÂÍÓÏÛ ÔÓ¯ÎÓÏÛ Ë Ú.Ô.àÁÓÏÂÚÓÔËfl – Ó‰Ë̇ÍÓ‚ÓÒÚ¸ Âه͈ËË ‚ Ó·ÓËı „·Á‡ı.àÁÓÏÂÚ˘ÂÒÍÓ ÛÔ‡ÊÌÂÌË – ÛÔ‡ÊÌÂÌËÂ Ò ÙËÁ˘ÂÒÍÓÈ Ì‡„ÛÁÍÓÈ Ì‡ Ï˚¯ˆ˚,ÍÓ„‰‡ ÒË· ÔËÍ·‰˚‚‡ÂÚÒfl Í ÒÚ‡Ú˘ÌÓÏÛ Ó·˙ÂÍÚÛ.àÁÓÏÂÚ˘ÂÒ͇fl ˜‡ÒÚˈ‡ – ‚ËÛÒ, ÍÓÚÓ˚È (‚ ÒÓÒÚÓflÌËË Í‡ÔÒˉ‡ ‚ËËÓ̇)ӷ·‰‡ÂÚ ËÍÓÒ‡˝‰‡Î¸ÌÓÈ ÒËÏÏÂÚËÂÈ.394ó‡ÒÚ¸ VII.
ê‡ÒÒÚÓflÌËfl ‚ ‡θÌÓÏ ÏËÂàÁÓÏÂÚ˘ÂÒÍËÈ ÔÓˆÂÒÒ – ÚÂÏÓ‰Ë̇Ï˘ÂÒÍËÈ ÔÓˆÂÒÒ ÔË ÔÓÒÚÓflÌÌÓÏÓ·˙ÂÏÂ.àÁÓÏÂÚ˘ÂÒ͇fl ÔÓÂ͈Ëfl – Ô‰ÒÚ‡‚ÎÂÌË ÚÂıÏÂÌ˚ı Ó·˙ÂÍÚÓ‚ ‚ ‰‚ÛıËÁÏÂÂÌËflı, ‚ ÍÓÚÓÓÏ Û„Î˚ ÏÂÊ‰Û ÚÂÏfl ÓÒflÏË ÔÓÂ͈ËË Ó‰Ë̇ÍÓ‚˚ ËÎË ‡‚Ì˚2π.3àÁÓÏÂÚ˘ÂÒ͇fl ÒËÒÚÂχ ÍËÒÚ‡ÎÎÓ‚ – Í۷˘ÂÒ͇fl ÍËÒÚ‡ÎÎÓ„‡Ù˘ÂÒ͇flÒËÒÚÂχ.åÂÚ˘ÂÒ͇fl ‡ÒËÏÏÂÚËfl ÍËÒÚ‡Î΢ÂÒÍÓÈ Â¯ÂÚÍË – ÒËÏÏÂÚËfl ·ÂÁ Û˜ÂÚ‡‡ÒÔÓÎÓÊÂÌËfl ‡ÚÓÏÓ‚ ‚ ·‡ÁËÒÌÓÈ ÍÎÂÚÍÂ.åÂÚ˘ÂÒÍË ÏÂ˚ ‰ÎËÌ˚äËÎÓÏÂÚ (ÍÏ) = 1000 ÏÂÚÓ‚ = 10 3 Ï.åÂÚ (Ï) = 10 ‰ÂˆËÏÂÚÓ‚ = 100 Ï.шËÏÂÚ (‰Ï) = 10 Ò‡ÌÚËÏÂÚÓ‚ = 10 –1 Ï.ë‡ÌÚËÏÂÚ (ÒÏ) = 10 ÏËÎÎËÏÂÚÓ‚ = 10–2 Ï.åËÎÎËÏÂÚ (ÏÏ) = 1000 ÏËÍÓÏÂÚÓ‚ = 10–3 Ï.åËÍÓÏÂÚ (ËÎË ÏËÍÓÌ, µ) = 1000 ̇ÌÓÏÂÚÓ‚ = 10 –6 Ï.ç‡ÌÓÏÂÚ (ÌÏ) = 10 Å = 10–9 Ï.ÑÎËÌ˚ 103t Ï, t = –8, –7, ..., –1,1,..., 7, 8 Û͇Á˚‚‡˛ÚÒfl Ò ÔËÒÚ‡‚͇ÏË: ÈÓÍÚÓ, ˆÂÔÚÓ,‡ÚÚÓ, ÙÂÏÚÓ, ÔËÍÓ, ̇ÌÓ, ÏËÍÓ, ÏËÎÎË, ÍËÎÓ, Ï„‡, „Ë„‡, Ú‡, ÔÂÚ‡, ˝ÍÒ‡, ˆÂÚÚ‡,ÈÓÚÚ‡ ÒÓÓÚ‚ÂÚÒÚ‚ÂÌÌÓ.àÏÔÂÒÍË ÏÂ˚ ‰ÎËÌ˚àÏÔÂÒÍËÏË Ï‡ÏË ‰ÎËÌ˚ (Ò΄͇ ÛÔÓfl‰Ó˜ÂÌÌ˚ÏË ÏÂʉÛ̇ӉÌ˚Ï Òӄ·¯ÂÌËÂÏ ÓÚ 1 ˲Îfl 1959 „.) fl‚Îfl˛ÚÒfl ÒÎÂ‰Û˛˘ËÂ:– ÎË„‡ = 3 ÏËÎË;– (‡ÏÂË͇ÌÒ͇fl „ÂÓ‰ÂÁ˘ÂÒ͇fl) ÏËÎfl = 5280 ÙÛÚÓ‚ ≈ 1609,347 Ï;– ÏÂʉÛ̇Ӊ̇fl ÏËÎfl = 1609,344 Ï;– fl‰ = 3 ÙÛÚ‡ = 0,9144 Ï;– ÙÛÚ = 12 ‰˛ÈÏÓ‚ = 0,3048 Ï;– ‰˛ÈÏ = 2,54 ÒÏ (‰Îfl Ó„ÌÂÒÚÂθÌÓ„Ó ÓÛÊËfl, ͇ÎË·);– ÎËÌËfl = 1/12 ‰˛Èχ;– ‡„‡Ú = 1/14 ‰˛Èχ;– ÏËÍË = 1/200 ‰˛Èχ;– ÏËÎ (·ËÚ‡ÌÒ͇fl Ú˚Òfl˜Ì‡fl) =1/1000 ‰˛Èχ (Ï Ë Î fl‚ÎflÂÚÒfl Ú‡ÍÊ ۄÎÓ‚ÓÈÏÂÓÈ π/3200 ≈ 0,01 ‡‰Ë‡Ì‡).ëÛ˘ÂÒÚ‚Û˛Ú Ú‡ÍÊ ÒÚ‡ËÌÌ˚ ÏÂ˚: fl˜ÏÂÌÌÓ ÁÂÌÓ – 1/3 ‰˛Èχ; ԇΈ –3/4 ‰˛Èχ; ·‰Ó̸ – 3 ‰˛Èχ; Û͇ – 4 ‰˛Èχ; ¯‡ÙÚÏÂÌÚ – 6 ‰˛ÈÏÓ‚, Ôfl‰¸ –9 ‰˛ÈÏÓ‚, ÎÓÍÓÚ¸ – 18 ‰˛ÈÏÓ‚.ÑÓÔÓÎÌËÚÂθÌÓ ËϲÚÒfl ÏÂ˚ ÁÂÏÎÂÏÂÌÓÈ ˆÂÔË: Ù‡ÎÓÌ„ = 10 ˜ÂÈÌÓ‚ = 1/8 ÏËÎË; ˜ÂÈÌ = 100 ÎËÌÍÓ‚ = 66 ÙÛÚÓ‚; ¯ÌÛ = 20 ÙÛÚÓ‚; Ó‰ (ËÎË ÔÓθ) = 16,5 ÙÛÚÓ‚;ÎËÌÍ = 7,92 ‰˛ÈÏÓ‚.
åËÎfl, Ù‡ÎÓÌ„ Ë Ò‡ÊÂ̸ (6 ÙÛÚÓ‚) ÔÓËÁÓ¯ÎË ÓÚ ÌÂÒÍÓθÍÓ·ÓΠÍÓÓÚÍËı „ÂÍÓ-ËÏÒÍËı ÏËÎÂÈ, ÒÚ‡‰ËÈ Ë Ó„ËÈ, ÛÔÓÏË̇ÂÏ˚ı ‚ çÓ‚ÓÏᇂÂÚÂ.ÅË·ÎÂÈÒÍËÏË Ï‡ÏË ‡Ì‡Îӄ˘ÌÓ„Ó ÚËÔ‡ ·˚ÎË: ÎÓÍÓÚ¸ Ë Â„Ó ÔÓËÁ‚Ó‰Ì˚‰ËÌˈ˚, ͇ÚÌ˚ 4, 1/2, 1/6 Ë 1/24, ̇Á˚‚‡ÂÏ˚ ÒÓÓÚ‚ÂÚÒÚ‚ÂÌÌÓ Ò‡ÊÂ̸˛, Ôfl‰¸˛,·‰Ó̸˛ Ë Ô‡Î¸ˆÂÏ. èË ˝ÚÓÏ ·‡ÁÓ‚‡fl ‰ÎË̇ ·Ë·ÎÂÈÒÍÓ„Ó ÎÓÍÚfl ÓÒÚ‡ÂÚÒfl ÌÂËÁ‚ÂÒÚÌÓÈ; ‚ ̇ÒÚÓfl˘Â ‚ÂÏfl Ô‰ÔÓ·„‡ÂÚÒfl, ˜ÚÓ Ó̇ ÒÓÒÚ‡‚ÎflÂÚ ÓÍÓÎÓ 17,6 ‰˛ÈÏÓ‚‰Îfl Ó·˘ÂÈ (ËÒÔÓθÁÛÂÏÓÈ ‚ ÍÓÏψËË) ÏÂ˚ ÎÓÍÚfl Ë ÓÍÓÎÓ 20–22 ‰˛ÈÏÓ‚ ‰ÎflÉ·‚‡ 27. åÂ˚ ‰ÎËÌ˚ Ë ¯Í‡Î˚395ÓÙˈˇθÌÓ„Ó ËÒÔÓθÁÓ‚‡ÌËfl (ÔËÏÂÌflÎÒfl ‚ ÒÚÓËÚÂθÒÚ‚Â).
í‡ÎÏۉ˘ÂÒÍËÈÎÓÍÓÚ¸ ‡‚ÂÌ 56,02 ÒÏ, Ú.Â. ÌÂÒÍÓθÍÓ ‰ÎËÌÌ 22 ‰˛ÈÏÓ‚.ä‡Í Û͇Á‡ÌÓ Ì‡ http://en.wikipedia.org/wiki/List_of_Strange_units_of_measurement,ÒÚ‡ËÌ̇fl ‰ËÌˈ‡ ‰ÎËÌ˚, ̇Á˚‚‡‚¯‡flÒfl ‰ËÒڇ̈ËÂÈ Ë ‡‚̇fl 221763 ‰˛ÈχÏ(ÓÍÓÎÓ 5633 Ï), ÓÔ‰ÂÎfl·Ҹ ‚ÂҸχ ÌÂÓ·˚˜ÌÓ, Í‡Í ‡‚̇fl 3 ÏËÎË + 3 Ù‡ÎÓÌ„‡ ++ 9 ˜ÂÈÌÓ‚ + 3 Ó‰‡ + 9 ÙÛÚÓ‚ + 9 ¯‡ÙÚÏÂÌÚÓ‚ + 9 ÛÍ + 9 fl˜ÏÂÌÌ˚ı ÁÂÂÌ.ÑÎfl Ó·ÓÁ̇˜ÂÌËfl ‡ÁÏÂÓ‚ χÚÂËË Ë Ó‰Âʉ˚ ËÒÔÓθÁÛ˛ÚÒfl ÒÚ‡˚ ‰ËÌˈ˚:ÛÎÓÌ – 40 fl‰Ó‚; ÎÓÍÓÚ¸ – 5/4 fl‰‡; „ÓΉ – 3/2 fl‰‡; ˜ÂÚ‚ÂÚ¸ (ËÎË Ô fl ‰ ¸) –1/4 fl‰‡; ԇΈ – 1/8 fl‰‡; ÌÓ„ÓÚ¸ – 1/16 fl‰‡.åÓÒÍË ‰ËÌˈ˚ ‰ÎËÌ˚åÓÒÍË ‰ËÌˈ˚ ‰ÎËÌ˚ (ÔËÏÂÌflÂÏ˚ ڇÍÊÂ Ë ‚ ‚ÓÁ‰Û¯ÌÓÈ Ì‡‚Ë„‡ˆËË):– ÏÓÒ͇fl ÎË„‡ = 3 ÏÓÒÍËı ÏËÎË;– ÏÓÒ͇fl ÏËÎfl = 1852 Ï;– „ÂÓ„‡Ù˘ÂÒ͇fl ÏËÎfl 1852 Ï (҉̠‡ÒÒÚÓflÌË ̇ ÔÓ‚ÂıÌÓÒÚË áÂÏÎË,Ô‰ÒÚ‡‚ÎÂÌÌÓ ӉÌÓÈ ÏËÌÛÚÓÈ ¯ËÓÚ˚);– ͇·ÂθÚÓ‚ = 120 Ò‡ÊÂÌÂÈ = 720 ÙÛÚÓ‚ = 219,456 Ï;– ÍÓÓÚÍËÈ Í‡·ÂθÚÓ‚ = 1/10 ÏÓÒÍÓÈ ÏËÎË 608 ÙÛÚÓ‚;Ò‡ÊÂ̸ = 6 ÙÛÚÓ‚.ÅÛχÊÌ˚ ÙÓχÚ˚ åéëÇ ¯ËÓÍÓ ËÒÔÓθÁÛÂÏÓÈ ÒËÒÚÂÏ ·ÛχÊÌ˚ı ÙÓχÚÓ‚ åéë ÓÚÌÓ¯ÂÌË ‚˚ÒÓÚ˚ÎËÒÚ‡ Í Â„Ó ¯ËËÌ fl‚ÎflÂÚÒfl ÓÚÌÓ¯ÂÌËÂÏ ãËıÚÂ̷„‡, Ú.Â.
2. ëËÒÚÂχ ‚Íβ˜‡ÂÚ ‚ Ò·fl ÙÓχÚ˚ An, Bn Ë (ËÒÔÓθÁÛÂÏ˚È ‰Îfl ÍÓÌ‚ÂÚÓ‚) ÙÓÏ‡Ú ën Ò 0 ≤ n ≤ 10Ë ¯ËËÌÓÈ ÎËÒÚ‡ 2 −1 / 4 − n / 2 , 2 − n / 2 Ë 2 −1 / 8 − n / 2 ÒÓÓÚ‚ÂÚÒÚ‚ÂÌÌÓ. ÇÒ ‡ÁÏÂ˚ Û͇Á‡Ì˚‚ ÏÂÚ‡ı, Ë ÒÓÓÚ‚ÂÚÒÚ‚ÂÌÌÓ ÔÎÓ˘‡‰¸ An ‡‚̇ 2 –n Ï2 . éÌË ÓÍÛ„Îfl˛ÚÒfl Ë Ó·˚˜ÌÓ‚˚‡Ê‡˛ÚÒfl ‚ ÏËÎÎËÏÂÚ‡ı, ̇ÔËÏÂ, ÙÓÏ‡Ú Ä4 – 210 × 297, ‡ ÙÓÏ‡Ú Ç7(ËÒÔÓθÁÛÂÏ˚È Ú‡ÍÊ ‰Îfl Ô‡ÒÔÓÚÓ‚ ‚ÓÔÂÈÒÍËı ÒÚ‡Ì Ë ëòÄ) ËÏÂÂÚ ‡ÁÏÂ˚88 × 125.èÓÎË„‡Ù˘ÂÒÍË ‰ËÌˈ˚ ‰ÎËÌ˚èÛÌÍÚ (PostScript) = 1/72 ‰˛Èχ = 100 „ÛÚÂ̷„ӂ = 3,527777778 ÒÏ.èÛÌÍÚ (íÂï) (ËÎË ÔÛÌÍÚ ÔËÌÚ‡) = 1/72,27 ‰˛Èχ = 3,514598035 ÒÏ.èÛÌÍÚ (ÄíÄ) = 3,514598 ÒÏ.äÛ (flÔÓÌÒ͇fl) (ËÎË Q, ˜ÂÚ‚ÂÚ¸) = 2,5 ÒÏ.èÛÌÍÚ (ÑˉÓ) = 1/72 ه̈ÛÁÒÍÓ„Ó ÍÓÓ΂ÒÍÓ„Ó ‰˛Èχ = 3,761 ÒÏ Ë ˆËˆÂÓ == 12 ÔÛÌÍÚÓ‚ ÑˉÓ.èË͇ (PostScript, íÂï ËÎË ÄíÄ) = 12 ÔÛÌÍÚÓ‚ ‚ ÒÓÓÚ‚ÂÚÒÚ‚Û˛˘ÂÈ ÒËÒÚÂÏÂ.í‚ËÔ = 1/20 ÔÛÌÍÚ‡ ‚ ÒÓÓÚ‚ÂÚÒÚ‚Û˛˘ÂÈ ÒËÒÚÂÏÂ.é˜Â̸ χÎ˚ ‰ËÌˈ˚ ‰ÎËÌ˚ÄÌ„ÒÚÂÏ (Å) = 10–10 Ï.ÄÌ„ÒÚÂÏ Á‚ÂÁ‰‡ (ËÎË Â‰ËÌˈ‡ ʼnÂ̇): Å ≈ 1,0000148 ‡Ì„ÒÚÂÏ (ËÒÔÓθÁÛÂÚÒfl Ò1965 „.
‰Îfl ËÁÏÂÂÌËfl ‰ÎËÌ ‚ÓÎÌ ÂÌÚ„ÂÌÓ‚ÒÍÓ„Ó Ë „‡Ïχ ËÁÎÛ˜ÂÌËfl, ‡ Ú‡ÍÊ ‡ÒÒÚÓflÌËÈ ÏÂÊ‰Û ‡ÚÓχÏË ‚ ÍËÒڇηı).ï ‰ËÌˈ‡ (ËÎË ÁË„·‡ÌÓ‚‡ ‰ËÌˈ‡) ≈ 1,0021 × 10–13 Ï (‡Ì ËÒÔÓθÁÓ‚‡Î‡Ò¸ ‰ÎflËÁÏÂÂÌËfl ‰ÎËÌ ‚ÓÎÌ ÂÌÚ„ÂÌÓ‚ÒÍÓ„Ó Ë „‡Ïχ ËÁÎÛ˜ÂÌËfl).ÅÓ (‡ÚÓÏ̇fl ‰ËÌˈ‡ ‰ÎËÌ˚): α 0, Ò‰ÌËÈ ‡‰ËÛÒ ≈ 5,291772 × 10–11 Ï Ó·ËÚ˚˝ÎÂÍÚÓ̇ ‡ÚÓχ ‚Ó‰ÓÓ‰‡ (‚ ÏÓ‰ÂÎË ÅÓ‡).396ó‡ÒÚ¸ VII. ê‡ÒÒÚÓflÌËfl ‚ ‡θÌÓÏ ÏËÂhè˂‰ÂÌ̇fl ÍÓÏÔÚÓÌÓ‚Ò͇fl ‰ÎË̇ ‚ÓÎÌ˚ ˝ÎÂÍÚÓ̇ (Ú.Â.) ‰Îfl χÒÒ˚mcr˝ÎÂÍÚÓ̇ me : λ C = αα 0 ≈ 3, 862 × 10 −13 Ï, „‰Â ˙ – Ô˂‰ÂÌ̇fl (Ú.Â. ‰ÂÎÂÌ̇fl ̇ 2π)1ÔÓÒÚÓflÌ̇fl è·Ì͇, Ò – ÒÍÓÓÒÚ¸ Ò‚ÂÚ‡ Ë α ≈ – ÔÓÒÚÓflÌ̇fl ÚÓÌÍÓÈ137ÒÚÛÍÚÛ˚.rä·ÒÒ˘ÂÒÍËÈ ‡‰ËÛÒ ˝ÎÂÍÚÓ̇: re : αλ C = α 2 α 0 ≈ 2, 81794 × 10 −15 Ï.äÓÏÔÚÓÌÓ‚Ò͇fl ‰ÎË̇ ‚ÓÎÌ˚ ÔÓÚÓ̇: ≈ 1,32141 × 10–15 Ï; ·Óθ¯‡fl ˜‡ÒÚ¸ ËÁÏÂÂÌËÈ ‰ÎËÌ ‚ ıӉ ˝ÍÒÔÂËÏÂÌÚÓ‚, Ò‚flÁ‡ÌÌ˚ı Ò ÙÛ̉‡ÏÂÌڇθÌ˚ÏË fl‰ÂÌ˚ÏËÒË·ÏË, fl‚ÎflÂÚÒfl  ͇ÚÌ˚ÏË.hGÑÎË̇ è·Ì͇ (̇ËÏÂ̸¯‡fl ÙËÁ˘ÂÒ͇fl ‰ÎË̇): lP =≈ 1, 6162 × 10 −35 Ï,c3„‰Â G – ÛÌË‚Â҇θ̇fl „‡‚ËÚ‡ˆËÓÌ̇fl ÔÓÒÚÓflÌ̇fl 縲ÚÓ̇.
é̇ fl‚ÎflÂÚÒfl Ú‡ÍÊÂÔ˂‰ÂÌÌÓÈ ÍÓÏÔÚÓÌÓ‚ÒÍÓÈ ‰ÎËÌÓÈ ‚ÓÎÌ˚ Ë ÔÓÎÓ‚ËÌÓÈ ‡‰ËÛÒ‡ ò‚‡ˆ˜‡È艇 ‰ÎfllhcχÒÒ˚ è·Ì͇ mP =≈ 2, 176 × 10 −8 Í„ . ÇÂÏfl è·Ì͇ t p = P ≈ 5, 4 × 10 −44 c.cc338439àÏÂÌÌÓ, 10 lP ≈ 1 ÏËΠëòÄ, 10 t P ≈ 54 c Ë 10 mP ≈ 21, 76 Í„ , Ú.Â. ·ÎËÁÍÓÍ 1 ڇ·ÌÚÛ (26 Í„ Ò·‡, χ ‚ÂÒ‡ ‚ Ñ‚ÌÂÈ ÉˆËË). äÓÚÂÎÎ(http://planck.com/humanscale.htm) Ô‰ÎÓÊËÎ "ÔÓÒÚÏÂÚ˘ÂÒÍËÈ" ‚‡Ë‡ÌÚ ‡‰‡ÔÚËÓ‚‡ÌÌÓÈ ÔÓ‰ ˜ÂÎÓ‚Â͇ ÒËÒÚÂÏ˚ ‰ËÌˈ è·Ì͇ ̇ ÓÒÌÓ‚Â ÚÂı ‚˚¯ÂÛ͇Á‡ÌÌ˚ı‰ËÌˈ, ̇Á‚‡‚ Ëı (Ô·ÌÍÓ‚ÒÍËÏË) ÏËÎÂÈ, ÏËÌÛÚÓÈ Ë Ú‡Î‡ÌÚÓÏ.ÄÒÚÓÌÓÏ˘ÂÒÍË ‰ËÌˈ˚ ‰ÎËÌ˚ê‡ÒÒÚÓflÌË ·Î‡ („‡Ìˈ‡ ÍÓÒÏ˘ÂÒÍÓ„Ó Ò‚ÂÚÓ‚Ó„Ó „ÓËÁÓÌÚ‡) ‡‚̇cDH =≈ 4, 22 ÔÍ ≈ 13, 7 Ò‚ÂÚÓ‚˚ı „Ë„‡ÎÂÚ (ËÒÔÓθÁÛÂÚÒfl ‰Îfl ËÁÏÂÂÌËfl ‡ÒÒÚÓflH01ÌËÈ d > åÔÍ ‚ ÚÂÏË̇ı ͇ÒÌÓ„Ó ÒÏ¢ÂÌËfl z: d = zD H, ÂÒÎË z ≤ 1, Ë2( z + 1)2 − 1d=DH , Ë̇˜Â).( z + 1)2 + 1ÉË„‡Ô‡ÒÂÍ (ÉÔÍ) = 103 Ï„‡Ô‡ÒÂÍÓ‚ (åÔÍ).·Î (ËÎË Ò‚ÂÚÓ„Ë„‡„Ó‰, Ò‚ÂÚÓ‚ÓÈ „Ë„‡„Ó‰, Ò‚ÂÚÓ‚ÓÈ Ga) = 109 (ÏΉ) Ò‚ÂÚÓ‚˚ıÎÂÚ ≈ 306,595 åÔÍ.儇ԇÒÂÍ = 10 3 ÍËÎÓÔ‡ÒÂÍÓ‚ ≈ 3,262 MLY (ÏÎÌ Ò‚.
ÎÂÚ).MLY (ÏËÎÎËÓÌ Ò‚ÂÚÓ‚˚ı ÎÂÚ) = 106 (ÏÎÌ) Ò‚. ÎÂÚ.äËÎÓÔ‡ÒÂÍ = 10 3 Ô‡ÒÂÍÓ‚.648000è‡ÒÂÍ =AU (‡ÒÚÓÌÓÏ˘ÂÒÍËı ‰ËÌˈ, ‡.Â.) ≈ 3,261624 Ò‚. „Ó‰‡π≈ 3,08568 × 1016 Ï (‡ÒÒÚÓflÌË ÓÚ ‚ÓÓ·‡Ê‡ÂÏÓÈ Á‚ÂÁ‰˚, ÍÓ„‰‡ ÔflÏ˚Â, Ôӂ‰ÂÌÌ˚ ÓÚ Ì ‰Ó áÂÏÎË Ë ‰Ó ëÓÎ̈‡, Ó·‡ÁÛ˛Ú Ï‡ÍÒËχθÌ˚È Û„ÓÎ, Ú.Â. Ô‡‡Î·ÍÒ,‚Â΢ËÌÓÈ ‚ ÒÂÍÛ̉Û).ë‚ÂÚÓ‚ÓÈ „Ó‰ ≈ 9,46073 × 1015 Ï ≈ 5,2595 × 105 Ò‚ÂÚÓ‚˚ı ÏËÌÛÚ ≈ π × 107 (‡ÒÒÚÓflÌËÂ, ÍÓÚÓÓ ‚ ‚‡ÍÛÛÏ ҂ÂÚ ÔÓıÓ‰ËÚ Á‡ Ó‰ËÌ „Ó‰; ËÒÔÓθÁÛÂÚÒfl ‰Îfl ËÁÏÂÂÌËfl‡ÒÒÚÓflÌËÈ ÏÂÊ‰Û Á‚ÂÁ‰‡ÏË).É·‚‡ 27. åÂ˚ ‰ÎËÌ˚ Ë ¯Í‡Î˚397ëÔ‡Ú (ÛÒڇ‚¯‡fl ‰ËÌˈ‡) ≈ 1012 Ï ≈ 6,6846 AU (‡ÒÚÓÌÓÏ˘ÂÒÍËı ‰ËÌˈ).ÄÒÚÓÌÓÏ˘ÂÒ͇fl ‰ËÌˈ‡ (AU) = 1,49597871 × 10 11 Ï ≈ 8,32 Ò‚ÂÚÓ‚˚ı ÏËÌÛÚ˚(҉̠‡ÒÒÚÓflÌË ÏÂÊ‰Û áÂÏÎÂÈ Ë ëÓÎ̈ÂÏ; ËÒÔÓθÁÛÂÚÒfl ‰Îfl ËÁÏÂÂÌËfl ‡ÒÒÚÓflÌËÈ ‚ ԉ·ı CÓÎ̘ÌÓÈ ÒËÒÚÂÏ˚).ë‚ÂÚÓ‚‡fl ÒÂÍÛ̉‡ ≈ 2,998 × 108 Ï.èËÍÓÔ‡ÒÂÍ ≈ 30,86 ÍÏ (ÒÏ.
Ú‡ÍÊ ‰Û„Ë Á‡·‡‚Ì˚ ‰ËÌˈ˚, ͇Í, ̇ÔËÏÂ,ÏËÍÓÒÚÓÎÂÚË ≈ 52,5 ÏËÌÛÚ˚, Ó·˚˜Ì‡fl ÔÓ‰ÓÎÊËÚÂθÌÓÒÚ¸ ‰ÓÍ·‰‡, Ë Ì‡ÌÓÒÚÓÎÂÚË ≈ π ÒÂÍÛ̉).27.2. òäÄãõ îàáàóÖëäàï ÑãàçÇ ‰‡ÌÌÓÏ ‡Á‰ÂΠ‡ÒÒχÚË‚‡ÂÚÒfl ̇·Ó ‡Á΢Ì˚ı ÔÓfl‰ÍÓ‚ ‚Â΢ËÌ˚ ‰ÎËÌ,‚˚‡ÊÂÌÌ˚ı ‚ ÏÂÚ‡ı.1,616 × 10–35 – ‰ÎË̇ è·Ì͇ (̇ËÏÂ̸¯‡fl ‚ÓÁÏÓÊ̇fl ÙËÁ˘ÂÒ͇fl ‰ÎË̇): ̇˝ÚÓÈ ¯Í‡Î ÓÊˉ‡ÂÚÒfl ̇΢ˠ"Í‚‡ÌÚÛÏÌÓÈ ÔÂÌ˚" (ÏÓ˘ÌÓ ËÒÍË‚ÎÂÌËÂ Ë ÚÛ·ÛÎÂ̈Ëfl ÔÓÒÚ‡ÌÒÚ‚‡-‚ÂÏÂÌË, ÌÂÚ „·‰ÍÓÈ ÔÓÒÚ‡ÌÒÚ‚ÂÌÌÓÈ „ÂÓÏÂÚËË); ‰ÓÏËÌËÛ˛˘ËÏË ÒÚÛÍÚÛ‡ÏË fl‚Îfl˛ÚÒfl χÎ˚ (ÏÌÓ„ÓÒ‚flÁÌ˚Â) ÔÓÒÚ‡ÌÒÚ‚ÂÌÌ˚ ‚ÓÓÌÍË Ë ÔÛÁ˚Ë, ‚ÓÁÌË͇˛˘ËÂ Ë ËÒ˜ÂÁ‡˛˘ËÂ.10–34 – ‰ÎË̇ Ô‰ÔÓ·„‡ÂÏÓÈ ÒÚÛÌ˚: å-ÚÂÓËfl Ô‰ÔÓ·„‡ÂÚ, ˜ÚÓ ‚Ò ÒËÎ˚ ˂Ҡ25 ˝ÎÂÏÂÌÚ‡Ì˚ı ˜‡ÒÚˈ Ó·˙flÒÌfl˛ÚÒfl ‚Ë·‡ˆËÂÈ Ú‡ÍËı ÒÚÛÌ Ë ÒÚÂÏËÚÒflÓ·˙‰ËÌËÚ¸ Í‚‡ÌÚÓ‚Û˛ ÏÂı‡ÌËÍÛ Ò Ó·˘ÂÈ ÚÂÓËÂÈ ÓÚÌÓÒËÚÂθÌÓÒÚË.10–24 = 1 ÈÓÍÚÓÏÂÚ.10–21 = 1 ˆÂÔÚÓÏÂÚ.10–18 = 1 ‡ÚÚÓÏÂÚ: ӷ·ÒÚ¸ Ò··˚ı fl‰ÂÌ˚ı ÒËÎ, ‡ÁÏ ͂‡Í‡.10–15 = 1 ÙÂÏÚÓÏÂÚ (·˚‚¯‡fl ÙÂÏË).1,3 × 10–15 – ӷ·ÒÚ¸ ·Óθ¯Ëı fl‰ÂÌ˚ı ÒËÎ, fl‰‡ Ò‰ÌËı ‡ÁÏÂÓ‚.10–12 = 1 ÔËÍÓÏÂÚ (‡Ì ̇Á˚‚‡ÎÒfl ·ËÍÓÌ ËÎË ÒÚ˄χ): ‡ÒÒÚÓflÌË ÏÂʉۇÚÓÏÌ˚ÏË fl‰‡ÏË ‚ ·ÂÎ˚ı ͇ÎËÍÓ‚˚ı Á‚ÂÁ‰‡ı.10–11 – ‰ÎË̇ ‚ÓÎÌ˚ ̇˷ÓΠÊÂÒÚÍÓ„Ó (ÍÓÓÚÍÓ‚ÓÎÌÓ‚Ó„Ó) ÂÌÚ„ÂÌÓ‚ÒÍÓ„ÓËÁÎÛ˜ÂÌËfl Ë Ì‡Ë·Óθ¯‡fl ‰ÎË̇ ‚ÓÎÌ˚ „‡Ïχ ËÁÎÛ˜ÂÌËfl.5 × 10–11 – ‰Ë‡ÏÂÚ Ì‡ËÏÂ̸¯Â„Ó ‡ÚÓχ (‚Ó‰ÓÓ‰‡ ç); 1,5 × 10–10 – ‰Ë‡ÏÂÚ̇ËÏÂ̸¯ÂÈ ÏÓÎÂÍÛÎ˚ (‚Ó‰ÓÓ‰ H 2 ).10–10 = 1 ‡Ì„ÒÚÂÏ – ‰Ë‡ÏÂÚ ÚËÔÓ‚Ó„Ó ‡ÚÓχ, Ô‰ÂÎ ‡Á¯‡˛˘ÂÈ ÒÔÓÒÓ·ÌÓÒÚË˝ÎÂÍÚÓÌÌÓ„Ó ÏËÍÓÒÍÓÔ‡.1,54 × 10–10 – ‰ÎË̇ ÚËÔÓ‚ÓÈ ÍÓ‚‡ÎÂÌÚÌÓÈ Ò‚flÁË (ë–ë).10–9 = 1 ̇ÌÓÏÂÚ – ‰Ë‡ÏÂÚ ÚËÔÓ‚ÓÈ ÏÓÎÂÍÛÎ˚.2 × 10–9 – ‰Ë‡ÏÂÚ ÒÔˇÎË Ñçä.10 –8 – ‰ÎË̇ ‚ÓÎÌ˚ ̇˷ÓΠÏfl„ÍÓ„Ó ÂÌÚ„ÂÌÓ‚ÒÍÓ„Ó ËÁÎÛ˜ÂÌËfl Ë Ò‡ÏÓ„Ó͇ÈÌÂ„Ó ÛθڇÙËÓÎÂÚÓ‚Ó„Ó ËÁÎÛ˜ÂÌËfl.1,1 × 10–8 – ‰Ë‡ÏÂÚ ÔËÓ̇ (̇ËÏÂ̸¯ÂÈ ·ËÓÎӄ˘ÂÒÍÓÈ ÒÛ˘ÌÓÒÚË, ÒÔÓÒÓ·ÌÓÈ ÍÒ‡ÏÓ‚ÓÒÔÓËÁ‚‰ÂÌ˲).4,5 × 10–8 – ̇ËÏÂ̸¯‡fl ‰Âڇθ ÍÓÏÔ¸˛ÚÂÌÓÈ ÏËÍÓÒıÂÏ˚ ‚ 2007 „.9 × 10–8 – ‚ËÛÒ ËÏÏÛÌÓ‰ÂÙˈËÚ‡ ˜ÂÎÓ‚Â͇ (Çàó); ‚ Ó·˘ÂÏ ÒÎÛ˜‡Â ‡ÁÏÂ˚ËÁ‚ÂÒÚÌ˚ı ‚ËÛÒÓ‚ ÍÓηβÚÒfl ‚ ԉ·ı ÓÚ 2 × 10–8 (‡‰ÂÌÓ‡ÒÒÓˆËËÓ‚‡ÌÌ˚e ‚ËÛÒ˚) ‰Ó 8 × 10–7 (ÏËÏË‚ËÛÒ).10–7: ‡ÁÏ ıÓÏÓÒÓÏ˚, χÍÒËχθÌ˚È ‡ÁÏ ˜‡ÒÚˈ˚, ÍÓÚÓ‡fl ÏÓÊÂÚ ÔÓÈÚ˘ÂÂÁ ıËۄ˘ÂÒÍÛ˛ χÒÍÛ.398ó‡ÒÚ¸ VII.